public String size_BigO() { return "YOURANSWER"; }
public String size_BigO() { return "YOURANSWER"; }
public String size_BigO() { /* Your algorithm for "size" should produce logic that has a Big-O "O(1)" performance level. I.e. the algorithm work (effort) should be constant (unchanged) as structure size grows to a very large size. For "O(1)", we answer "1" as shown below in this method (completed for you) */ return "1"; }
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